Base | Representation |
---|---|
bin | 10000011000000011101… |
… | …100011010010001110011 |
3 | 10222120201010011010212201 |
4 | 100120003230122101303 |
5 | 121414200402431141 |
6 | 2220550422404031 |
7 | 144206026055116 |
oct | 20300354322163 |
9 | 3876633133781 |
10 | 1125343405171 |
11 | 3a428a018447 |
12 | 162123290617 |
13 | 821724c8ccb |
14 | 3c6772c257d |
15 | 1e4158a8031 |
hex | 10603b1a473 |
1125343405171 has 2 divisors, whose sum is σ = 1125343405172. Its totient is φ = 1125343405170.
The previous prime is 1125343405159. The next prime is 1125343405223. The reversal of 1125343405171 is 1715043435211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1125343405171 - 211 = 1125343403123 is a prime.
It is a super-2 number, since 2×11253434051712 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1125343405171.
It is not a weakly prime, because it can be changed into another prime (1125343405141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562671702585 + 562671702586.
It is an arithmetic number, because the mean of its divisors is an integer number (562671702586).
Almost surely, 21125343405171 is an apocalyptic number.
1125343405171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1125343405171 is an equidigital number, since it uses as much as digits as its factorization.
1125343405171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 37.
The spelling of 1125343405171 in words is "one trillion, one hundred twenty-five billion, three hundred forty-three million, four hundred five thousand, one hundred seventy-one".
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