11253551300137 has 2 divisors, whose sum is σ = 11253551300138. Its totient is φ = 11253551300136.

The previous prime is 11253551300071. The next prime is 11253551300149. The reversal of 11253551300137 is 73100315535211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11202917749776 + 50633550361 = 3347076^2 + 225019^2 .

It is a cyclic number.

It is not a de Polignac number, because 11253551300137 - 2⁷ = 11253551300009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11253551300096 and 11253551300105.

It is not a weakly prime, because it can be changed into another prime (11253558300137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5626775650068 + 5626775650069.

It is an arithmetic number, because the mean of its divisors is an integer number (5626775650069).

Almost surely, 2^{11253551300137} is an apocalyptic number.

It is an amenable number.

11253551300137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11253551300137 is an equidigital number, since it uses as much as digits as its factorization.

11253551300137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47250, while the sum is 37.

Adding to 11253551300137 its reverse (73100315535211), we get a palindrome (84353866835348).

The spelling of 11253551300137 in words is "eleven trillion, two hundred fifty-three billion, five hundred fifty-one million, three hundred thousand, one hundred thirty-seven".