Base | Representation |
---|---|
bin | 1010001111000010101111… |
… | …1011010111111001101011 |
3 | 1110211211101100011021110211 |
4 | 2203300223323113321223 |
5 | 2433334233113101303 |
6 | 35533450551521551 |
7 | 2241020330524102 |
oct | 243605373277153 |
9 | 43754340137424 |
10 | 11253551300203 |
11 | 3649671369603 |
12 | 131901b6892b7 |
13 | 6382891716c4 |
14 | 2ac96389b039 |
15 | 147ae616566d |
hex | a3c2bed7e6b |
11253551300203 has 2 divisors, whose sum is σ = 11253551300204. Its totient is φ = 11253551300202.
The previous prime is 11253551300191. The next prime is 11253551300227. The reversal of 11253551300203 is 30200315535211.
It is a weak prime.
It is an emirp because it is prime and its reverse (30200315535211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11253551300203 is a prime.
It is not a weakly prime, because it can be changed into another prime (11253551300503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5626775650101 + 5626775650102.
It is an arithmetic number, because the mean of its divisors is an integer number (5626775650102).
Almost surely, 211253551300203 is an apocalyptic number.
11253551300203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11253551300203 is an equidigital number, since it uses as much as digits as its factorization.
11253551300203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 11253551300203 its reverse (30200315535211), we get a palindrome (41453866835414).
The spelling of 11253551300203 in words is "eleven trillion, two hundred fifty-three billion, five hundred fifty-one million, three hundred thousand, two hundred three".
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