112540125373 has 4 divisors (see below), whose sum is σ = 121197058108. Its totient is φ = 103883192640.

The previous prime is 112540125337. The next prime is 112540125377. The reversal of 112540125373 is 373521045211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10020410404 + 102519714969 = 100102^2 + 320187^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112540125373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112540125377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4328466348 + ... + 4328466373.

It is an arithmetic number, because the mean of its divisors is an integer number (30299264527).

Almost surely, 2^112540125373 is an apocalyptic number.

112540125373 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

112540125373 is a deficient number, since it is larger than the sum of its proper divisors (8656932735).

112540125373 is an equidigital number, since it uses as much as digits as its factorization.

112540125373 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8656932734.

The product of its (nonzero) digits is 25200, while the sum is 34.

The spelling of 112540125373 in words is "one hundred twelve billion, five hundred forty million, one hundred twenty-five thousand, three hundred seventy-three".