Base | Representation |
---|---|
bin | 10000011011111011000… |
… | …100010111101011001001 |
3 | 10222222102100120211220001 |
4 | 100123323010113223021 |
5 | 122001200334031223 |
6 | 2222514321003001 |
7 | 144413622454366 |
oct | 20337304275311 |
9 | 3888370524801 |
10 | 1129493658313 |
11 | 3a60197a7019 |
12 | 162aa1183461 |
13 | 826842a78b7 |
14 | 3c94c58946d |
15 | 1e5a9e0c9ad |
hex | 106fb117ac9 |
1129493658313 has 2 divisors, whose sum is σ = 1129493658314. Its totient is φ = 1129493658312.
The previous prime is 1129493658289. The next prime is 1129493658373. The reversal of 1129493658313 is 3138563949211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 901517967289 + 227975691024 = 949483^2 + 477468^2 .
It is an emirp because it is prime and its reverse (3138563949211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1129493658313 - 233 = 1120903723721 is a prime.
It is not a weakly prime, because it can be changed into another prime (1129493658373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 564746829156 + 564746829157.
It is an arithmetic number, because the mean of its divisors is an integer number (564746829157).
Almost surely, 21129493658313 is an apocalyptic number.
It is an amenable number.
1129493658313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1129493658313 is an equidigital number, since it uses as much as digits as its factorization.
1129493658313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4199040, while the sum is 55.
The spelling of 1129493658313 in words is "one trillion, one hundred twenty-nine billion, four hundred ninety-three million, six hundred fifty-eight thousand, three hundred thirteen".
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