Base | Representation |
---|---|
bin | 11001101100010111011111… |
… | …011100100111011110010100 |
3 | 112211002200212022111120201220 |
4 | 121230113133130213132110 |
5 | 104302343042103130343 |
6 | 1040155300413450340 |
7 | 32541661263000432 |
oct | 3154273734473624 |
9 | 484080768446656 |
10 | 113000043411348 |
11 | 3300705a667515 |
12 | 108101b9aa09b0 |
13 | 4b08b20ac0842 |
14 | 1dc93348d7d52 |
15 | d0e5ccb7e183 |
hex | 66c5df727794 |
113000043411348 has 48 divisors (see below), whose sum is σ = 264407272684800. Its totient is φ = 37560911883264.
The previous prime is 113000043411347. The next prime is 113000043411361. The reversal of 113000043411348 is 843114340000311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113000043411347) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51999040 + ... + 54128552.
It is an arithmetic number, because the mean of its divisors is an integer number (5508484847600).
Almost surely, 2113000043411348 is an apocalyptic number.
It is an amenable number.
113000043411348 is an abundant number, since it is smaller than the sum of its proper divisors (151407229273452).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113000043411348 is a wasteful number, since it uses less digits than its factorization.
113000043411348 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2141936 (or 2141934 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 33.
Adding to 113000043411348 its reverse (843114340000311), we get a palindrome (956114383411659).
The spelling of 113000043411348 in words is "one hundred thirteen trillion, forty-three million, four hundred eleven thousand, three hundred forty-eight".
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