11300004404431 has 4 divisors (see below), whose sum is σ = 11300038335664. Its totient is φ = 11299970473200.

The previous prime is 11300004404419. The next prime is 11300004404449. The reversal of 11300004404431 is 13440440000311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11300004404431 is a prime.

It is a super-2 number, since 2×11300004404431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11300004404396 and 11300004404405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11300004414431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16461075 + ... + 17133796.

It is an arithmetic number, because the mean of its divisors is an integer number (2825009583916).

Almost surely, 2^{11300004404431} is an apocalyptic number.

11300004404431 is a deficient number, since it is larger than the sum of its proper divisors (33931233).

11300004404431 is an equidigital number, since it uses as much as digits as its factorization.

11300004404431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33931232.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 11300004404431 its reverse (13440440000311), we get a palindrome (24740444404742).

The spelling of 11300004404431 in words is "eleven trillion, three hundred billion, four million, four hundred four thousand, four hundred thirty-one".