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113001000000 = 2635675381
BaseRepresentation
bin110100100111101100…
…0100110110001000000
3101210200020022120110020
41221033120212301000
53322411224000000
6123524551333440
711110161436410
oct1511730466100
9353606276406
10113001000000
1143a181338a9
1219a97981280
13a86b171655
14567d9aa640
152e157d7ba0
hex1a4f626c40

113001000000 has 392 divisors, whose sum is σ = 427190781888. Its totient is φ = 25824000000.

The previous prime is 113000999953. The next prime is 113001000017. The reversal of 113001000000 is 100311.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 20997310 + ... + 21002690.

Almost surely, 2113001000000 is an apocalyptic number.

113001000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113001000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (213595390944).

113001000000 is an abundant number, since it is smaller than the sum of its proper divisors (314189781888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113001000000 is an frugal number, since it uses more digits than its factorization.

113001000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5433 (or 5398 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 6.

Adding to 113001000000 its reverse (100311), we get a palindrome (113001100311).

The spelling of 113001000000 in words is "one hundred thirteen billion, one million", and thus it is an aban number.