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1130021121422 = 2565010560711
BaseRepresentation
bin10000011100011010100…
…000011110110110001110
311000000210010002202020202
4100130122200132312032
5122003240401341142
62223042522213502
7144432656022614
oct20343240366616
94000703082222
101130021121422
113a626a510946
12163009954292
138273965704b
143c99c64d6b4
151e5db39d032
hex1071a81ed8e

1130021121422 has 4 divisors (see below), whose sum is σ = 1695031682136. Its totient is φ = 565010560710.

The previous prime is 1130021121413. The next prime is 1130021121469. The reversal of 1130021121422 is 2241211200311.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1130021121394 and 1130021121403.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282505280354 + ... + 282505280357.

It is an arithmetic number, because the mean of its divisors is an integer number (423757920534).

Almost surely, 21130021121422 is an apocalyptic number.

1130021121422 is a deficient number, since it is larger than the sum of its proper divisors (565010560714).

1130021121422 is an equidigital number, since it uses as much as digits as its factorization.

1130021121422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565010560713.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1130021121422 its reverse (2241211200311), we get a palindrome (3371232321733).

The spelling of 1130021121422 in words is "one trillion, one hundred thirty billion, twenty-one million, one hundred twenty-one thousand, four hundred twenty-two".

Divisors: 1 2 565010560711 1130021121422