Base | Representation |
---|---|
bin | 1010010001110000100100… |
… | …1001000000000100110011 |
3 | 1111000021211020002012001211 |
4 | 2210130021021000010303 |
5 | 2440120313322412243 |
6 | 40011125035140551 |
7 | 2244261536544346 |
oct | 244341111000463 |
9 | 44007736065054 |
10 | 11300212310323 |
11 | 3667436287092 |
12 | 13260822a4757 |
13 | 63c7b422a271 |
14 | 2b0d0c98245d |
15 | 148e27804d9d |
hex | a4709240133 |
11300212310323 has 2 divisors, whose sum is σ = 11300212310324. Its totient is φ = 11300212310322.
The previous prime is 11300212310171. The next prime is 11300212310329. The reversal of 11300212310323 is 32301321200311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11300212310323 - 217 = 11300212179251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11300212310294 and 11300212310303.
It is not a weakly prime, because it can be changed into another prime (11300212310329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650106155161 + 5650106155162.
It is an arithmetic number, because the mean of its divisors is an integer number (5650106155162).
Almost surely, 211300212310323 is an apocalyptic number.
11300212310323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300212310323 is an equidigital number, since it uses as much as digits as its factorization.
11300212310323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11300212310323 its reverse (32301321200311), we get a palindrome (43601533510634).
The spelling of 11300212310323 in words is "eleven trillion, three hundred billion, two hundred twelve million, three hundred ten thousand, three hundred twenty-three".
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