Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11001001010100110 |
3 | 1002011112100022121202 |
4 | 22201202321022212 |
5 | 141120323312124 |
6 | 5105150442502 |
7 | 550013141420 |
oct | 124142711246 |
9 | 32145308552 |
10 | 11300213414 |
11 | 4879748656 |
12 | 2234503432 |
13 | 10b119b619 |
14 | 792adb810 |
15 | 4620e15ae |
hex | 2a18b92a6 |
11300213414 has 16 divisors (see below), whose sum is σ = 19447177248. Its totient is φ = 4824102912.
The previous prime is 11300213389. The next prime is 11300213417. The reversal of 11300213414 is 41431200311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11300213417) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1566749 + ... + 1573944.
It is an arithmetic number, because the mean of its divisors is an integer number (1215448578).
Almost surely, 211300213414 is an apocalyptic number.
11300213414 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
11300213414 is a deficient number, since it is larger than the sum of its proper divisors (8146963834).
11300213414 is a wasteful number, since it uses less digits than its factorization.
11300213414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3140959.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 11300213414 its reverse (41431200311), we get a palindrome (52731413725).
The spelling of 11300213414 in words is "eleven billion, three hundred million, two hundred thirteen thousand, four hundred fourteen".
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