Base | Representation |
---|---|
bin | 1010010001110000100111… |
… | …0010010010000101010011 |
3 | 1111000021211222102222121012 |
4 | 2210130021302102011103 |
5 | 2440120324110210422 |
6 | 40011130103121135 |
7 | 2244262030535366 |
oct | 244341162220523 |
9 | 44007758388535 |
10 | 11300223131987 |
11 | 36674413a8609 |
12 | 1326085a431ab |
13 | 63c7b6548b0a |
14 | 2b0d1019c0dd |
15 | 148e287414e2 |
hex | a4709c92153 |
11300223131987 has 2 divisors, whose sum is σ = 11300223131988. Its totient is φ = 11300223131986.
The previous prime is 11300223131969. The next prime is 11300223132007. The reversal of 11300223131987 is 78913132200311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11300223131987 - 224 = 11300206354771 is a prime.
It is not a weakly prime, because it can be changed into another prime (11300223121987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650111565993 + 5650111565994.
It is an arithmetic number, because the mean of its divisors is an integer number (5650111565994).
Almost surely, 211300223131987 is an apocalyptic number.
11300223131987 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300223131987 is an equidigital number, since it uses as much as digits as its factorization.
11300223131987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 41.
The spelling of 11300223131987 in words is "eleven trillion, three hundred billion, two hundred twenty-three million, one hundred thirty-one thousand, nine hundred eighty-seven".
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