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113002302023113 is a prime number
BaseRepresentation
bin11001101100011001100110…
…000100100010010111001001
3112211002220200201110221121111
4121230121212010202113021
5104302412203304214423
61040200312455410321
732542101246612406
oct3154314604422711
9484086621427544
10113002302023113
1133008009589a08
121081072a3839a1
134b090c0a042c9
141dc94aa8712ad
15d0e6b10c760d
hex66c6661225c9

113002302023113 has 2 divisors, whose sum is σ = 113002302023114. Its totient is φ = 113002302023112.

The previous prime is 113002302022979. The next prime is 113002302023131. The reversal of 113002302023113 is 311320203200311.

Together with next prime (113002302023131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57379822052809 + 55622479970304 = 7574947^2 + 7458048^2 .

It is a cyclic number.

It is not a de Polignac number, because 113002302023113 - 29 = 113002302022601 is a prime.

It is not a weakly prime, because it can be changed into another prime (113002902023113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56501151011556 + 56501151011557.

It is an arithmetic number, because the mean of its divisors is an integer number (56501151011557).

Almost surely, 2113002302023113 is an apocalyptic number.

It is an amenable number.

113002302023113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113002302023113 is an equidigital number, since it uses as much as digits as its factorization.

113002302023113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 113002302023113 its reverse (311320203200311), we get a palindrome (424322505223424).

The spelling of 113002302023113 in words is "one hundred thirteen trillion, two billion, three hundred two million, twenty-three thousand, one hundred thirteen".