Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11101100101001001 |
3 | 1002011112101020102111 |
4 | 22201202331211021 |
5 | 141120324401442 |
6 | 5105151102321 |
7 | 550013245222 |
oct | 124142754511 |
9 | 32145336374 |
10 | 11300231497 |
11 | 48797601a5 |
12 | 22345119a1 |
13 | 10b11a6919 |
14 | 792b04249 |
15 | 4620e6b17 |
hex | 2a18bd949 |
11300231497 has 2 divisors, whose sum is σ = 11300231498. Its totient is φ = 11300231496.
The previous prime is 11300231491. The next prime is 11300231549. The reversal of 11300231497 is 79413200311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10945135161 + 355096336 = 104619^2 + 18844^2 .
It is an emirp because it is prime and its reverse (79413200311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11300231497 - 23 = 11300231489 is a prime.
It is a super-2 number, since 2×113002314972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11300231491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650115748 + 5650115749.
It is an arithmetic number, because the mean of its divisors is an integer number (5650115749).
Almost surely, 211300231497 is an apocalyptic number.
It is an amenable number.
11300231497 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300231497 is an equidigital number, since it uses as much as digits as its factorization.
11300231497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 31.
The spelling of 11300231497 in words is "eleven billion, three hundred million, two hundred thirty-one thousand, four hundred ninety-seven".
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