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11300311000213 = 16369327061351
BaseRepresentation
bin1010010001110000111100…
…0001011110010010010101
31111000022002002210011010221
42210130033001132102111
52440121014104001323
640011142522314341
72244264145442104
oct244341701362225
944008062704127
1011300311000213
113667486a63284
1213260ab3589b1
1363c7cb802651
142b0d1bb1203b
15148e312eb55d
hexa470f05e495

11300311000213 has 4 divisors (see below), whose sum is σ = 11369638061728. Its totient is φ = 11230983938700.

The previous prime is 11300311000159. The next prime is 11300311000217. The reversal of 11300311000213 is 31200011300311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11300311000213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11300311000217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34663530513 + ... + 34663530838.

It is an arithmetic number, because the mean of its divisors is an integer number (2842409515432).

Almost surely, 211300311000213 is an apocalyptic number.

It is an amenable number.

11300311000213 is a deficient number, since it is larger than the sum of its proper divisors (69327061515).

11300311000213 is an equidigital number, since it uses as much as digits as its factorization.

11300311000213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69327061514.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11300311000213 its reverse (31200011300311), we get a palindrome (42500322300524).

The spelling of 11300311000213 in words is "eleven trillion, three hundred billion, three hundred eleven million, two hundred thirteen", and thus it is an aban number.

Divisors: 1 163 69327061351 11300311000213