31200011300311 has 4 divisors (see below), whose sum is σ = 35657155771792. Its totient is φ = 26742866828832.

The previous prime is 31200011300303. The next prime is 31200011300323. The reversal of 31200011300311 is 11300311000213.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 31200011300311 - 2³ = 31200011300303 is a prime.

It is a super-4 number, since 4×31200011300311⁴ (a number of 55 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31200011300911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2228572235730 + ... + 2228572235743.

It is an arithmetic number, because the mean of its divisors is an integer number (8914288942948).

Almost surely, 2^{31200011300311} is an apocalyptic number.

31200011300311 is a deficient number, since it is larger than the sum of its proper divisors (4457144471481).

31200011300311 is an equidigital number, since it uses as much as digits as its factorization.

31200011300311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4457144471480.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 31200011300311 its reverse (11300311000213), we get a palindrome (42500322300524).

The spelling of 31200011300311 in words is "thirty-one trillion, two hundred billion, eleven million, three hundred thousand, three hundred eleven".