Base | Representation |
---|---|
bin | 1010010001110000111100… |
… | …0110001011010101110110 |
3 | 1111000022002012002210200002 |
4 | 2210130033012023111312 |
5 | 2440121014412431314 |
6 | 40011143004551302 |
7 | 2244264162066155 |
oct | 244341706132566 |
9 | 44008065083602 |
10 | 11300312233334 |
11 | 3667487725793 |
12 | 13260ab852532 |
13 | 63c7cbb449c7 |
14 | 2b0d1bd5359c |
15 | 148e31491ade |
hex | a470f18b576 |
11300312233334 has 4 divisors (see below), whose sum is σ = 16950468350004. Its totient is φ = 5650156116666.
The previous prime is 11300312233267. The next prime is 11300312233361. The reversal of 11300312233334 is 43333221300311.
11300312233334 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11300312233297 and 11300312233306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2825078058332 + ... + 2825078058335.
It is an arithmetic number, because the mean of its divisors is an integer number (4237617087501).
Almost surely, 211300312233334 is an apocalyptic number.
11300312233334 is a deficient number, since it is larger than the sum of its proper divisors (5650156116670).
11300312233334 is an equidigital number, since it uses as much as digits as its factorization.
11300312233334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5650156116669.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 11300312233334 its reverse (43333221300311), we get a palindrome (54633533533645).
The spelling of 11300312233334 in words is "eleven trillion, three hundred billion, three hundred twelve million, two hundred thirty-three thousand, three hundred thirty-four".
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