Base | Representation |
---|---|
bin | 10101000011000111… |
… | …00111101110010010 |
3 | 1002011112201000012201 |
4 | 22201203213232102 |
5 | 141120400412424 |
6 | 5105154513414 |
7 | 550014564406 |
oct | 124143475622 |
9 | 32145630181 |
10 | 11300404114 |
11 | 487986895a |
12 | 223459586a |
13 | 10b123736c |
14 | 792b4b106 |
15 | 46212cd44 |
hex | 2a18e7b92 |
11300404114 has 16 divisors (see below), whose sum is σ = 17713764288. Its totient is φ = 5396543152.
The previous prime is 11300404111. The next prime is 11300404127. The reversal of 11300404114 is 41140400311.
11300404114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11300404091 and 11300404100.
It is not an unprimeable number, because it can be changed into a prime (11300404111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150292 + ... + 212575.
It is an arithmetic number, because the mean of its divisors is an integer number (1107110268).
Almost surely, 211300404114 is an apocalyptic number.
11300404114 is a deficient number, since it is larger than the sum of its proper divisors (6413360174).
11300404114 is a wasteful number, since it uses less digits than its factorization.
11300404114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 363569.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11300404114 its reverse (41140400311), we get a palindrome (52440804425).
The spelling of 11300404114 in words is "eleven billion, three hundred million, four hundred four thousand, one hundred fourteen".
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