Base | Representation |
---|---|
bin | 10101000011000111… |
… | …00111101110001111 |
3 | 1002011112201000012121 |
4 | 22201203213232033 |
5 | 141120400412421 |
6 | 5105154513411 |
7 | 550014564403 |
oct | 124143475617 |
9 | 32145630177 |
10 | 11300404111 |
11 | 4879868957 |
12 | 2234595867 |
13 | 10b1237369 |
14 | 792b4b103 |
15 | 46212cd41 |
hex | 2a18e7b8f |
11300404111 has 2 divisors, whose sum is σ = 11300404112. Its totient is φ = 11300404110.
The previous prime is 11300404097. The next prime is 11300404127. The reversal of 11300404111 is 11140400311.
It is an a-pointer prime, because the next prime (11300404127) can be obtained adding 11300404111 to its sum of digits (16).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11300404111 - 225 = 11266849679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300404151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650202055 + 5650202056.
It is an arithmetic number, because the mean of its divisors is an integer number (5650202056).
Almost surely, 211300404111 is an apocalyptic number.
11300404111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300404111 is an equidigital number, since it uses as much as digits as its factorization.
11300404111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11300404111 its reverse (11140400311), we get a palindrome (22440804422).
The spelling of 11300404111 in words is "eleven billion, three hundred million, four hundred four thousand, one hundred eleven".
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