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11300414473 is a prime number
BaseRepresentation
bin10101000011000111…
…01010010000001001
31002011112201112102101
422201203222100021
5141120401230343
65105155033401
7550014636535
oct124143522011
932145645371
1011300414473
114879875717
12223459b861
1310b123bcaa
14792b50bc5
15462130e4d
hex2a18ea409

11300414473 has 2 divisors, whose sum is σ = 11300414474. Its totient is φ = 11300414472.

The previous prime is 11300414417. The next prime is 11300414479. The reversal of 11300414473 is 37441400311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7525909504 + 3774504969 = 86752^2 + 61437^2 .

It is a cyclic number.

It is not a de Polignac number, because 11300414473 - 213 = 11300406281 is a prime.

It is a super-3 number, since 3×113004144733 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11300414479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650207236 + 5650207237.

It is an arithmetic number, because the mean of its divisors is an integer number (5650207237).

Almost surely, 211300414473 is an apocalyptic number.

It is an amenable number.

11300414473 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300414473 is an equidigital number, since it uses as much as digits as its factorization.

11300414473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 11300414473 its reverse (37441400311), we get a palindrome (48741814784).

The spelling of 11300414473 in words is "eleven billion, three hundred million, four hundred fourteen thousand, four hundred seventy-three".