Base | Representation |
---|---|
bin | 10000011100011100011… |
… | …101100010000001111001 |
3 | 11000000212101210012101011 |
4 | 100130130131202001321 |
5 | 122003322244334312 |
6 | 2223050052553521 |
7 | 144433534453264 |
oct | 20343435420171 |
9 | 4000771705334 |
10 | 1130053902457 |
11 | 3a6286a70807 |
12 | 1630189228a1 |
13 | 82743393acc |
14 | 3c9a2b43cdb |
15 | 1e5de1c5da7 |
hex | 1071c762079 |
1130053902457 has 2 divisors, whose sum is σ = 1130053902458. Its totient is φ = 1130053902456.
The previous prime is 1130053902403. The next prime is 1130053902499. The reversal of 1130053902457 is 7542093500311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 846011804521 + 284042097936 = 919789^2 + 532956^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130053902457 - 239 = 580298088569 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130053902157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565026951228 + 565026951229.
It is an arithmetic number, because the mean of its divisors is an integer number (565026951229).
Almost surely, 21130053902457 is an apocalyptic number.
It is an amenable number.
1130053902457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130053902457 is an equidigital number, since it uses as much as digits as its factorization.
1130053902457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 1130053902457 in words is "one trillion, one hundred thirty billion, fifty-three million, nine hundred two thousand, four hundred fifty-seven".
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