Base | Representation |
---|---|
bin | 11001101100100001000011… |
… | …101000111111000111000011 |
3 | 112211010200101010000022001202 |
4 | 121230201003220333013003 |
5 | 104303030110430410313 |
6 | 1040204115514451415 |
7 | 32542503640125551 |
oct | 3154410350770703 |
9 | 484120333008052 |
10 | 113010314310083 |
11 | 33010450289783 |
12 | 108121a5733b6b |
13 | 4b09a99959c08 |
14 | 1dc9a2aa16bd1 |
15 | d0e9ce6ed558 |
hex | 66c843a3f1c3 |
113010314310083 has 2 divisors, whose sum is σ = 113010314310084. Its totient is φ = 113010314310082.
The previous prime is 113010314310073. The next prime is 113010314310211. The reversal of 113010314310083 is 380013413010311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113010314310083 - 232 = 113006019342787 is a prime.
It is a super-2 number, since 2×1130103143100832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113010314310043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505157155041 + 56505157155042.
It is an arithmetic number, because the mean of its divisors is an integer number (56505157155042).
Almost surely, 2113010314310083 is an apocalyptic number.
113010314310083 is a deficient number, since it is larger than the sum of its proper divisors (1).
113010314310083 is an equidigital number, since it uses as much as digits as its factorization.
113010314310083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 113010314310083 its reverse (380013413010311), we get a palindrome (493023727320394).
The spelling of 113010314310083 in words is "one hundred thirteen trillion, ten billion, three hundred fourteen million, three hundred ten thousand, eighty-three".
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