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113011032313129 is a prime number
BaseRepresentation
bin11001101100100001101110…
…011011111100110100101001
3112211010202020011001122002011
4121230201232123330310221
5104303033043233010004
61040204315044035521
732542530506061106
oct3154415633746451
9484122204048064
10113011032313129
1133010789605025
1210812366092ba1
134b09b826307a2
141dc9a98119aad
15d0ea2277a004
hex66c86e6fcd29

113011032313129 has 2 divisors, whose sum is σ = 113011032313130. Its totient is φ = 113011032313128.

The previous prime is 113011032313117. The next prime is 113011032313169. The reversal of 113011032313129 is 921313230110311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66076544047504 + 46934488265625 = 8128748^2 + 6850875^2 .

It is a cyclic number.

It is not a de Polignac number, because 113011032313129 - 29 = 113011032312617 is a prime.

It is a super-4 number, since 4×1130110323131294 (a number of 57 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113011032313129.

It is not a weakly prime, because it can be changed into another prime (113011032313169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505516156564 + 56505516156565.

It is an arithmetic number, because the mean of its divisors is an integer number (56505516156565).

Almost surely, 2113011032313129 is an apocalyptic number.

It is an amenable number.

113011032313129 is a deficient number, since it is larger than the sum of its proper divisors (1).

113011032313129 is an equidigital number, since it uses as much as digits as its factorization.

113011032313129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 31.

The spelling of 113011032313129 in words is "one hundred thirteen trillion, eleven billion, thirty-two million, three hundred thirteen thousand, one hundred twenty-nine".