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113011433 is a prime number
BaseRepresentation
bin1101011110001…
…10101011101001
321212122120112122
412233012223221
5212412331213
615114121025
72541403253
oct657065351
9255576478
10113011433
1158879187
1231a20175
131a54ac92
141101acd3
159dc4d08
hex6bc6ae9

113011433 has 2 divisors, whose sum is σ = 113011434. Its totient is φ = 113011432.

The previous prime is 113011429. The next prime is 113011441. The reversal of 113011433 is 334110311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92698384 + 20313049 = 9628^2 + 4507^2 .

It is a cyclic number.

It is not a de Polignac number, because 113011433 - 22 = 113011429 is a prime.

It is not a weakly prime, because it can be changed into another prime (113011033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505716 + 56505717.

It is an arithmetic number, because the mean of its divisors is an integer number (56505717).

Almost surely, 2113011433 is an apocalyptic number.

It is an amenable number.

113011433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113011433 is an equidigital number, since it uses as much as digits as its factorization.

113011433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 113011433 is about 10630.6835622174. The cubic root of 113011433 is about 483.4751171306.

Adding to 113011433 its reverse (334110311), we get a palindrome (447121744).

The spelling of 113011433 in words is "one hundred thirteen million, eleven thousand, four hundred thirty-three".