Base | Representation |
---|---|
bin | 10000011100100000011… |
… | …110101000100101101011 |
3 | 11000001001002121100212201 |
4 | 100130200132220211223 |
5 | 122003442023102311 |
6 | 2223100501321031 |
7 | 144435313361452 |
oct | 20344036504553 |
9 | 4001032540781 |
10 | 1130121300331 |
11 | 3a6311014831 |
12 | 163037406177 |
13 | 827543310ca |
14 | 3c9aba89b99 |
15 | 1e5e508a9c1 |
hex | 107207a896b |
1130121300331 has 2 divisors, whose sum is σ = 1130121300332. Its totient is φ = 1130121300330.
The previous prime is 1130121300317. The next prime is 1130121300383. The reversal of 1130121300331 is 1330031210311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1130121300331 - 29 = 1130121299819 is a prime.
It is a super-2 number, since 2×11301213003312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1130121300299 and 1130121300308.
It is not a weakly prime, because it can be changed into another prime (1130121300311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565060650165 + 565060650166.
It is an arithmetic number, because the mean of its divisors is an integer number (565060650166).
Almost surely, 21130121300331 is an apocalyptic number.
1130121300331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130121300331 is an equidigital number, since it uses as much as digits as its factorization.
1130121300331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1130121300331 its reverse (1330031210311), we get a palindrome (2460152510642).
The spelling of 1130121300331 in words is "one trillion, one hundred thirty billion, one hundred twenty-one million, three hundred thousand, three hundred thirty-one".
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