Base | Representation |
---|---|
bin | 10000011100100000100… |
… | …001110001100000000011 |
3 | 11000001001011011011201211 |
4 | 100130200201301200003 |
5 | 122003442230421032 |
6 | 2223100531110551 |
7 | 144435323356624 |
oct | 20344041614003 |
9 | 4001034134654 |
10 | 1130122123267 |
11 | 3a6311527045 |
12 | 163037742457 |
13 | 8275455b857 |
14 | 3c9abc21a4b |
15 | 1e5e519e747 |
hex | 10720871803 |
1130122123267 has 2 divisors, whose sum is σ = 1130122123268. Its totient is φ = 1130122123266.
The previous prime is 1130122123211. The next prime is 1130122123301. The reversal of 1130122123267 is 7623212210311.
It is a strong prime.
It is an emirp because it is prime and its reverse (7623212210311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1130122123267 - 215 = 1130122090499 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130122123567) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565061061633 + 565061061634.
It is an arithmetic number, because the mean of its divisors is an integer number (565061061634).
Almost surely, 21130122123267 is an apocalyptic number.
1130122123267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130122123267 is an equidigital number, since it uses as much as digits as its factorization.
1130122123267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 1130122123267 its reverse (7623212210311), we get a palindrome (8753334333578).
The spelling of 1130122123267 in words is "one trillion, one hundred thirty billion, one hundred twenty-two million, one hundred twenty-three thousand, two hundred sixty-seven".
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