Base | Representation |
---|---|
bin | 10000011100100001000… |
… | …111111000011001101001 |
3 | 11000001001211221201001222 |
4 | 100130201013320121221 |
5 | 122004002310104001 |
6 | 2223101525151425 |
7 | 144435504314333 |
oct | 20344107703151 |
9 | 4001054851058 |
10 | 1130132113001 |
11 | 3a631712a521 |
12 | 16303ab5b575 |
13 | 82756648838 |
14 | 3c9ad2a2453 |
15 | 1e5e5ec461b |
hex | 107211f8669 |
1130132113001 has 2 divisors, whose sum is σ = 1130132113002. Its totient is φ = 1130132113000.
The previous prime is 1130132112943. The next prime is 1130132113037. The reversal of 1130132113001 is 1003112310311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 953942890000 + 176189223001 = 976700^2 + 419749^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130132113001 - 214 = 1130132096617 is a prime.
It is a super-3 number, since 3×11301321130013 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1130132112001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565066056500 + 565066056501.
It is an arithmetic number, because the mean of its divisors is an integer number (565066056501).
Almost surely, 21130132113001 is an apocalyptic number.
It is an amenable number.
1130132113001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130132113001 is an equidigital number, since it uses as much as digits as its factorization.
1130132113001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1130132113001 its reverse (1003112310311), we get a palindrome (2133244423312).
The spelling of 1130132113001 in words is "one trillion, one hundred thirty billion, one hundred thirty-two million, one hundred thirteen thousand, one".
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