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113020000000000 = 2115105651
BaseRepresentation
bin11001101100101010000100…
…111100111101100000000000
3112211011121101010100022210221
4121230222010330331200000
5104303204430000000000
61040212400552432424
732543265650130562
oct3154520474754000
9484147333308727
10113020000000000
1133014570635995
12108140493a8714
134b0a9814a8c92
141dca2a911d332
15d0ed99bc261a
hex66ca84f3d800

113020000000000 has 264 divisors, whose sum is σ = 282531000073140. Its totient is φ = 45200000000000.

The previous prime is 113019999999997. The next prime is 113020000000007. The reversal of 113020000000000 is 20311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113020000000007) by changing a digit.

It is a polite number, since it can be written in 21 ways as a sum of consecutive naturals, for example, 19999997175 + ... + 20000002825.

Almost surely, 2113020000000000 is an apocalyptic number.

113020000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113020000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (141265500036570).

113020000000000 is an abundant number, since it is smaller than the sum of its proper divisors (169511000073140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113020000000000 is an frugal number, since it uses more digits than its factorization.

113020000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5723 (or 5658 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 113020000000000 its reverse (20311), we get a palindrome (113020000020311).

The spelling of 113020000000000 in words is "one hundred thirteen trillion, twenty billion", and thus it is an aban number.