1130200001333 has 8 divisors (see below), whose sum is σ = 1243035026688. Its totient is φ = 1021064485104.

The previous prime is 1130200001321. The next prime is 1130200001347. The reversal of 1130200001333 is 3331000020311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1130200001333 - 2⁴ = 1130200001317 is a prime.

It is a super-2 number, since 2×1130200001333² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130200001353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 924876641 + ... + 924877862.

It is an arithmetic number, because the mean of its divisors is an integer number (155379378336).

Almost surely, 2^{1130200001333} is an apocalyptic number.

1130200001333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1130200001333 is a deficient number, since it is larger than the sum of its proper divisors (112835025355).

1130200001333 is a wasteful number, since it uses less digits than its factorization.

1130200001333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1849754563.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1130200001333 its reverse (3331000020311), we get a palindrome (4461200021644).

The spelling of 1130200001333 in words is "one trillion, one hundred thirty billion, two hundred million, one thousand, three hundred thirty-three".