Base | Representation |
---|---|
bin | 11001101100101010001100… |
… | …000111111100110000011011 |
3 | 112211011121200111202021021011 |
4 | 121230222030013330300123 |
5 | 104303210201300233201 |
6 | 1040212420531354351 |
7 | 32543301640630036 |
oct | 3154521407746033 |
9 | 484147614667234 |
10 | 113020120321051 |
11 | 33014622546979 |
12 | 108140817529b7 |
13 | 4b0a9a03b6078 |
14 | 1dca2bb0c001d |
15 | d0eda553d151 |
hex | 66ca8c1fcc1b |
113020120321051 has 2 divisors, whose sum is σ = 113020120321052. Its totient is φ = 113020120321050.
The previous prime is 113020120321027. The next prime is 113020120321057. The reversal of 113020120321051 is 150123021020311.
It is a strong prime.
It is an emirp because it is prime and its reverse (150123021020311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113020120321051 - 211 = 113020120319003 is a prime.
It is not a weakly prime, because it can be changed into another prime (113020120321057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56510060160525 + 56510060160526.
It is an arithmetic number, because the mean of its divisors is an integer number (56510060160526).
Almost surely, 2113020120321051 is an apocalyptic number.
113020120321051 is a deficient number, since it is larger than the sum of its proper divisors (1).
113020120321051 is an equidigital number, since it uses as much as digits as its factorization.
113020120321051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 113020120321051 its reverse (150123021020311), we get a palindrome (263143141341362).
The spelling of 113020120321051 in words is "one hundred thirteen trillion, twenty billion, one hundred twenty million, three hundred twenty-one thousand, fifty-one".
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