Base | Representation |
---|---|
bin | 10000011100100101011… |
… | …010001100110110100111 |
3 | 11000001020212021011201212 |
4 | 100130211122030312213 |
5 | 122004124212233411 |
6 | 2223113014342035 |
7 | 144440336461142 |
oct | 20344532146647 |
9 | 4001225234655 |
10 | 1130204024231 |
11 | 3a6353786497 |
12 | 16305b05a91b |
13 | 82768506269 |
14 | 3c9b8a61059 |
15 | 1e5ec47b68b |
hex | 1072568cda7 |
1130204024231 has 16 divisors (see below), whose sum is σ = 1170900931200. Its totient is φ = 1090228271328.
The previous prime is 1130204024197. The next prime is 1130204024267. The reversal of 1130204024231 is 1324204020311.
It is a cyclic number.
It is not a de Polignac number, because 1130204024231 - 238 = 855326117287 is a prime.
It is a super-2 number, since 2×11302040242312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1130204024197 and 1130204024206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130204024291) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1046180 + ... + 1831638.
It is an arithmetic number, because the mean of its divisors is an integer number (73181308200).
Almost surely, 21130204024231 is an apocalyptic number.
1130204024231 is a deficient number, since it is larger than the sum of its proper divisors (40696906969).
1130204024231 is a wasteful number, since it uses less digits than its factorization.
1130204024231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 785918.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1130204024231 its reverse (1324204020311), we get a palindrome (2454408044542).
The spelling of 1130204024231 in words is "one trillion, one hundred thirty billion, two hundred four million, twenty-four thousand, two hundred thirty-one".
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