1130204024291 has 2 divisors, whose sum is σ = 1130204024292. Its totient is φ = 1130204024290.

The previous prime is 1130204024267. The next prime is 1130204024293. The reversal of 1130204024291 is 1924204020311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130204024291 is a prime.

It is a super-2 number, since 2×1130204024291² (a number of 25 digits) contains 22 as substring.

Together with 1130204024293, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1130204024293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565102012145 + 565102012146.

It is an arithmetic number, because the mean of its divisors is an integer number (565102012146).

Almost surely, 2^{1130204024291} is an apocalyptic number.

1130204024291 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130204024291 is an equidigital number, since it uses as much as digits as its factorization.

1130204024291 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

The spelling of 1130204024291 in words is "one trillion, one hundred thirty billion, two hundred four million, twenty-four thousand, two hundred ninety-one".