Base | Representation |
---|---|
bin | 1010010001110111011001… |
… | …0101100111100101001101 |
3 | 1111000110112220100122122220 |
4 | 2210131312111213211031 |
5 | 2440133041322200123 |
6 | 40012030521525553 |
7 | 2244355123520430 |
oct | 244356625474515 |
9 | 44013486318586 |
10 | 11302044334413 |
11 | 3668196423988 |
12 | 13264b39438b9 |
13 | 63ca169506a1 |
14 | 2b1043dd3817 |
15 | 148ed3586ce3 |
hex | a477656794d |
11302044334413 has 64 divisors (see below), whose sum is σ = 18190710300672. Its totient is φ = 6102272563200.
The previous prime is 11302044334411. The next prime is 11302044334429. The reversal of 11302044334413 is 31443344020311.
It is not a de Polignac number, because 11302044334413 - 21 = 11302044334411 is a prime.
It is a super-2 number, since 2×113020443344132 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11302044334411) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19666081 + ... + 20232617.
It is an arithmetic number, because the mean of its divisors is an integer number (284229848448).
Almost surely, 211302044334413 is an apocalyptic number.
It is an amenable number.
11302044334413 is a deficient number, since it is larger than the sum of its proper divisors (6888665966259).
11302044334413 is a wasteful number, since it uses less digits than its factorization.
11302044334413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 567074.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 11302044334413 its reverse (31443344020311), we get a palindrome (42745388354724).
The spelling of 11302044334413 in words is "eleven trillion, three hundred two billion, forty-four million, three hundred thirty-four thousand, four hundred thirteen".
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