Base | Representation |
---|---|
bin | 10000011100100101111… |
… | …001011011100101001001 |
3 | 11000001021102200002220011 |
4 | 100130211321123211021 |
5 | 122004133311223032 |
6 | 2223113510031521 |
7 | 144440466166261 |
oct | 20344571334511 |
9 | 4001242602804 |
10 | 1130212211017 |
11 | 3a635836832a |
12 | 1630619485a1 |
13 | 8276a111706 |
14 | 3c9b9b927a1 |
15 | 1e5ed047247 |
hex | 10725e5b949 |
1130212211017 has 2 divisors, whose sum is σ = 1130212211018. Its totient is φ = 1130212211016.
The previous prime is 1130212210997. The next prime is 1130212211033. The reversal of 1130212211017 is 7101122120311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1107175346176 + 23036864841 = 1052224^2 + 151779^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130212211017 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130212251017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565106105508 + 565106105509.
It is an arithmetic number, because the mean of its divisors is an integer number (565106105509).
Almost surely, 21130212211017 is an apocalyptic number.
It is an amenable number.
1130212211017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130212211017 is an equidigital number, since it uses as much as digits as its factorization.
1130212211017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 22.
Adding to 1130212211017 its reverse (7101122120311), we get a palindrome (8231334331328).
The spelling of 1130212211017 in words is "one trillion, one hundred thirty billion, two hundred twelve million, two hundred eleven thousand, seventeen".
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