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11302131000 = 23353192337233
BaseRepresentation
bin10101000011010100…
…01101010100111000
31002011122221202001110
422201222031110320
5141121321143000
65105255520320
7550035346146
oct124152152470
932148852043
1011302131000
11487a838336
1222350890a0
1310b16c03a4
1479307a596
1546236e850
hex2a1a8d538

11302131000 has 512 divisors, whose sum is σ = 39949977600. Its totient is φ = 2645913600.

The previous prime is 11302130993. The next prime is 11302131007. The reversal of 11302131000 is 13120311.

It is an interprime number because it is at equal distance from previous prime (11302130993) and next prime (11302131007).

It is a super-2 number, since 2×113021310002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11302131007) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 48506884 + ... + 48507116.

It is an arithmetic number, because the mean of its divisors is an integer number (78027300).

Almost surely, 211302131000 is an apocalyptic number.

11302131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11302131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19974988800).

11302131000 is an abundant number, since it is smaller than the sum of its proper divisors (28647846600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11302131000 is a wasteful number, since it uses less digits than its factorization.

11302131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 336 (or 322 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 11302131000 its reverse (13120311), we get a palindrome (11315251311).

The spelling of 11302131000 in words is "eleven billion, three hundred two million, one hundred thirty-one thousand".