Base | Representation |
---|---|
bin | 10000011100100110000… |
… | …001110101001011111011 |
3 | 11000001021120210222111222 |
4 | 100130212001311023323 |
5 | 122004134342204201 |
6 | 2223114025142255 |
7 | 144440524000223 |
oct | 20344601651373 |
9 | 4001246728458 |
10 | 1130214413051 |
11 | 3a6359631799 |
12 | 16306262a98b |
13 | 8276a702aa9 |
14 | 3c9ba1a7083 |
15 | 1e5ed32e91b |
hex | 107260752fb |
1130214413051 has 2 divisors, whose sum is σ = 1130214413052. Its totient is φ = 1130214413050.
The previous prime is 1130214413011. The next prime is 1130214413059. The reversal of 1130214413051 is 1503144120311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130214413051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1130214413051.
It is not a weakly prime, because it can be changed into another prime (1130214413059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565107206525 + 565107206526.
It is an arithmetic number, because the mean of its divisors is an integer number (565107206526).
Almost surely, 21130214413051 is an apocalyptic number.
1130214413051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130214413051 is an equidigital number, since it uses as much as digits as its factorization.
1130214413051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 1130214413051 its reverse (1503144120311), we get a palindrome (2633358533362).
The spelling of 1130214413051 in words is "one trillion, one hundred thirty billion, two hundred fourteen million, four hundred thirteen thousand, fifty-one".
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