Search a number
-
+
113022003112 = 2314127750389
BaseRepresentation
bin110100101000010100…
…0101110011110101000
3101210201200211122022021
41221100220232132220
53322432113044422
6123531021434224
711110535114104
oct1512050563650
9353650748267
10113022003112
1143a28a79847
1219aa2a0b974
13a872616525
1456826b6904
152e17585dc7
hex1a50a2e7a8

113022003112 has 8 divisors (see below), whose sum is σ = 211916255850. Its totient is φ = 56511001552.

The previous prime is 113022003109. The next prime is 113022003131. The reversal of 113022003112 is 211300220311.

It can be written as a sum of positive squares in only one way, i.e., 68490030436 + 44531972676 = 261706^2 + 211026^2 .

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-3 number, since 3×1130220031123 (a number of 34 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7063875187 + ... + 7063875202.

Almost surely, 2113022003112 is an apocalyptic number.

It is an amenable number.

113022003112 is a deficient number, since it is larger than the sum of its proper divisors (98894252738).

113022003112 is a wasteful number, since it uses less digits than its factorization.

113022003112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14127750395 (or 14127750391 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 113022003112 its reverse (211300220311), we get a palindrome (324322223423).

The spelling of 113022003112 in words is "one hundred thirteen billion, twenty-two million, three thousand, one hundred twelve".

Divisors: 1 2 4 8 14127750389 28255500778 56511001556 113022003112