Base | Representation |
---|---|
bin | 1010010001111000000101… |
… | …1111001110001100000111 |
3 | 1111000111000221100122002021 |
4 | 2210132001133032030013 |
5 | 2440133432214314343 |
6 | 40012101243224011 |
7 | 2244362554540630 |
oct | 244360137161407 |
9 | 44014027318067 |
10 | 11302231401223 |
11 | 3668281a82a54 |
12 | 1326546518007 |
13 | 63ca46629cc9 |
14 | 2b1060baa887 |
15 | 148ee4bd90ed |
hex | a47817ce307 |
11302231401223 has 8 divisors (see below), whose sum is σ = 12916882395680. Its totient is φ = 9687592033920.
The previous prime is 11302231401203. The next prime is 11302231401277. The reversal of 11302231401223 is 32210413220311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11302231401223 - 25 = 11302231401191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11302231401203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 713478 + ... + 4807651.
It is an arithmetic number, because the mean of its divisors is an integer number (1614610299460).
Almost surely, 211302231401223 is an apocalyptic number.
11302231401223 is a deficient number, since it is larger than the sum of its proper divisors (1614650994457).
11302231401223 is an equidigital number, since it uses as much as digits as its factorization.
11302231401223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5813577.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11302231401223 its reverse (32210413220311), we get a palindrome (43512644621534).
The spelling of 11302231401223 in words is "eleven trillion, three hundred two billion, two hundred thirty-one million, four hundred one thousand, two hundred twenty-three".
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