Base | Representation |
---|---|
bin | 10101000011010110… |
… | …10110101000000001 |
3 | 1002011200111222220012 |
4 | 22201223112220001 |
5 | 141121410244413 |
6 | 5105310154305 |
7 | 550041036362 |
oct | 124153265001 |
9 | 32150458805 |
10 | 11302431233 |
11 | 487aa22965 |
12 | 22351b2995 |
13 | 10b1796c42 |
14 | 793117b69 |
15 | 4623cd7a8 |
hex | 2a1ad6a01 |
11302431233 has 2 divisors, whose sum is σ = 11302431234. Its totient is φ = 11302431232.
The previous prime is 11302431211. The next prime is 11302431241. The reversal of 11302431233 is 33213420311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10399308529 + 903122704 = 101977^2 + 30052^2 .
It is a cyclic number.
It is not a de Polignac number, because 11302431233 - 218 = 11302169089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11302431199 and 11302431208.
It is not a weakly prime, because it can be changed into another prime (11302431253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651215616 + 5651215617.
It is an arithmetic number, because the mean of its divisors is an integer number (5651215617).
Almost surely, 211302431233 is an apocalyptic number.
It is an amenable number.
11302431233 is a deficient number, since it is larger than the sum of its proper divisors (1).
11302431233 is an equidigital number, since it uses as much as digits as its factorization.
11302431233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11302431233 its reverse (33213420311), we get a palindrome (44515851544).
The spelling of 11302431233 in words is "eleven billion, three hundred two million, four hundred thirty-one thousand, two hundred thirty-three".
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