Base | Representation |
---|---|
bin | 11001101100101110001100… |
… | …000000000001111100011011 |
3 | 112211012000202200120202011122 |
4 | 121230232030000001330123 |
5 | 104303242444240244233 |
6 | 1040214410523115455 |
7 | 32543513215615265 |
oct | 3154561400017433 |
9 | 484160680522148 |
10 | 113024413212443 |
11 | 330164257997a7 |
12 | 10814a7b372b8b |
13 | 4b0b2058b6aa5 |
14 | 1dca5a72b6b35 |
15 | d1005736ad98 |
hex | 66cb8c001f1b |
113024413212443 has 2 divisors, whose sum is σ = 113024413212444. Its totient is φ = 113024413212442.
The previous prime is 113024413212377. The next prime is 113024413212481. The reversal of 113024413212443 is 344212314420311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113024413212443 - 210 = 113024413211419 is a prime.
It is not a weakly prime, because it can be changed into another prime (113024413212493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56512206606221 + 56512206606222.
It is an arithmetic number, because the mean of its divisors is an integer number (56512206606222).
Almost surely, 2113024413212443 is an apocalyptic number.
113024413212443 is a deficient number, since it is larger than the sum of its proper divisors (1).
113024413212443 is an equidigital number, since it uses as much as digits as its factorization.
113024413212443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 113024413212443 its reverse (344212314420311), we get a palindrome (457236727632754).
The spelling of 113024413212443 in words is "one hundred thirteen trillion, twenty-four billion, four hundred thirteen million, two hundred twelve thousand, four hundred forty-three".
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