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113025403 is a prime number
BaseRepresentation
bin1101011110010…
…10000101111011
321212200021201001
412233022011323
5212413303103
615114305431
72541462061
oct657120573
9255607631
10113025403
1158888727
1231a28277
131a55444a
1411022031
159dc901d
hex6bca17b

113025403 has 2 divisors, whose sum is σ = 113025404. Its totient is φ = 113025402.

The previous prime is 113025391. The next prime is 113025413. The reversal of 113025403 is 304520311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113025403 - 213 = 113017211 is a prime.

It is not a weakly prime, because it can be changed into another prime (113025413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56512701 + 56512702.

It is an arithmetic number, because the mean of its divisors is an integer number (56512702).

Almost surely, 2113025403 is an apocalyptic number.

113025403 is a deficient number, since it is larger than the sum of its proper divisors (1).

113025403 is an equidigital number, since it uses as much as digits as its factorization.

113025403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 113025403 is about 10631.3406022006. The cubic root of 113025403 is about 483.4950380328.

Adding to 113025403 its reverse (304520311), we get a palindrome (417545714).

The spelling of 113025403 in words is "one hundred thirteen million, twenty-five thousand, four hundred three".