Base | Representation |
---|---|
bin | 10000011100101000011… |
… | …010000010000110011001 |
3 | 11000001101100220001100122 |
4 | 100130220122002012121 |
5 | 122004230100434313 |
6 | 2223122012243025 |
7 | 144441520064213 |
oct | 20345032020631 |
9 | 4001340801318 |
10 | 1130254311833 |
11 | 3a637a103299 |
12 | 163073a70475 |
13 | 82775a6253a |
14 | 3c9c15d15b3 |
15 | 1e601ab1708 |
hex | 10728682199 |
1130254311833 has 2 divisors, whose sum is σ = 1130254311834. Its totient is φ = 1130254311832.
The previous prime is 1130254311787. The next prime is 1130254311881. The reversal of 1130254311833 is 3381134520311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 832103366809 + 298150945024 = 912197^2 + 546032^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130254311833 - 212 = 1130254307737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1130254311793 and 1130254311802.
It is not a weakly prime, because it can be changed into another prime (1130254313833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565127155916 + 565127155917.
It is an arithmetic number, because the mean of its divisors is an integer number (565127155917).
Almost surely, 21130254311833 is an apocalyptic number.
It is an amenable number.
1130254311833 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130254311833 is an equidigital number, since it uses as much as digits as its factorization.
1130254311833 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 1130254311833 in words is "one trillion, one hundred thirty billion, two hundred fifty-four million, three hundred eleven thousand, eight hundred thirty-three".
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