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1130254311833 is a prime number
BaseRepresentation
bin10000011100101000011…
…010000010000110011001
311000001101100220001100122
4100130220122002012121
5122004230100434313
62223122012243025
7144441520064213
oct20345032020631
94001340801318
101130254311833
113a637a103299
12163073a70475
1382775a6253a
143c9c15d15b3
151e601ab1708
hex10728682199

1130254311833 has 2 divisors, whose sum is σ = 1130254311834. Its totient is φ = 1130254311832.

The previous prime is 1130254311787. The next prime is 1130254311881. The reversal of 1130254311833 is 3381134520311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 832103366809 + 298150945024 = 912197^2 + 546032^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130254311833 - 212 = 1130254307737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130254311793 and 1130254311802.

It is not a weakly prime, because it can be changed into another prime (1130254313833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565127155916 + 565127155917.

It is an arithmetic number, because the mean of its divisors is an integer number (565127155917).

Almost surely, 21130254311833 is an apocalyptic number.

It is an amenable number.

1130254311833 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130254311833 is an equidigital number, since it uses as much as digits as its factorization.

1130254311833 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 1130254311833 in words is "one trillion, one hundred thirty billion, two hundred fifty-four million, three hundred eleven thousand, eight hundred thirty-three".