Base | Representation |
---|---|
bin | 1010010001111010111101… |
… | …0111000000100001000000 |
3 | 1111000120000120111022010200 |
4 | 2210132233113000201000 |
5 | 2440142021224000000 |
6 | 40012305454325200 |
7 | 2244420621165063 |
oct | 244365727004100 |
9 | 44016016438120 |
10 | 11303001000000 |
11 | 36686374399a6 |
12 | 13267201b9800 |
13 | 63cb39bc73b8 |
14 | 2b10d50a08da |
15 | 14903c558500 |
hex | a47af5c0840 |
11303001000000 has 588 divisors, whose sum is σ = 40706947694400. Its totient is φ = 2998512000000.
The previous prime is 11303000999963. The next prime is 11303001000079. The reversal of 11303001000000 is 10030311.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is an unprimeable number.
It is a polite number, since it can be written in 83 ways as a sum of consecutive naturals, for example, 1790996845 + ... + 1791003155.
Almost surely, 211303001000000 is an apocalyptic number.
11303001000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11303001000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20353473847200).
11303001000000 is an abundant number, since it is smaller than the sum of its proper divisors (29403946694400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11303001000000 is an frugal number, since it uses more digits than its factorization.
11303001000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6558 (or 6520 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 9.
Adding to 11303001000000 its reverse (10030311), we get a palindrome (11303011030311).
The spelling of 11303001000000 in words is "eleven trillion, three hundred three billion, one million", and thus it is an aban number.
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