Search a number
-
+
1130300323102 = 2565150161551
BaseRepresentation
bin10000011100101011001…
…001100011010100011110
311000001111120110122221201
4100130223021203110132
5122004323340314402
62223130334350114
7144442616136646
oct20345311432436
94001446418851
101130300323102
113a63a307a235
1216308735b33a
1382782452242
143c9c776b526
151e605b4e687
hex1072b26351e

1130300323102 has 4 divisors (see below), whose sum is σ = 1695450484656. Its totient is φ = 565150161550.

The previous prime is 1130300323081. The next prime is 1130300323109. The reversal of 1130300323102 is 2013230030311.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1130300323102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130300323109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282575080774 + ... + 282575080777.

It is an arithmetic number, because the mean of its divisors is an integer number (423862621164).

Almost surely, 21130300323102 is an apocalyptic number.

1130300323102 is a deficient number, since it is larger than the sum of its proper divisors (565150161554).

1130300323102 is an equidigital number, since it uses as much as digits as its factorization.

1130300323102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565150161553.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1130300323102 its reverse (2013230030311), we get a palindrome (3143530353413).

The spelling of 1130300323102 in words is "one trillion, one hundred thirty billion, three hundred million, three hundred twenty-three thousand, one hundred two".

Divisors: 1 2 565150161551 1130300323102