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11303012141300 = 225211101223503907
BaseRepresentation
bin1010010001111011000000…
…0001100000100011110100
31111000120001100110100010102
42210132300001200203310
52440142032102010200
640012310533213232
72244421114660025
oct244366001404364
944016040410112
1011303012141300
113668642759590
121326723a91218
1363cb3c2c8599
142b10d6760c4c
1514903d5096d5
hexa47b00608f4

11303012141300 has 288 divisors, whose sum is σ = 27227361337344. Its totient is φ = 4038730560000.

The previous prime is 11303012141299. The next prime is 11303012141341. The reversal of 11303012141300 is 314121030311.

It is a super-2 number, since 2×113030121413002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 12461975447 + ... + 12461976353.

It is an arithmetic number, because the mean of its divisors is an integer number (94539449088).

Almost surely, 211303012141300 is an apocalyptic number.

11303012141300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11303012141300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13613680668672).

11303012141300 is an abundant number, since it is smaller than the sum of its proper divisors (15924349196044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11303012141300 is a wasteful number, since it uses less digits than its factorization.

11303012141300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1759 (or 1752 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11303012141300 its reverse (314121030311), we get a palindrome (11617133171611).

The spelling of 11303012141300 in words is "eleven trillion, three hundred three billion, twelve million, one hundred forty-one thousand, three hundred".