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113030132993 is a prime number
BaseRepresentation
bin110100101000100011…
…1101111010100000001
3101210202021010200101222
41221101013233110001
53322441203223433
6123531512004425
711110664164301
oct1512107572401
9353667120358
10113030132993
1143a32621958
1219aa5690715
13a874201acb
1456837d1601
152e1813eb98
hex1a511ef501

113030132993 has 2 divisors, whose sum is σ = 113030132994. Its totient is φ = 113030132992.

The previous prime is 113030132989. The next prime is 113030133071. The reversal of 113030132993 is 399231030311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73499547664 + 39530585329 = 271108^2 + 198823^2 .

It is an emirp because it is prime and its reverse (399231030311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113030132993 - 22 = 113030132989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113030132093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56515066496 + 56515066497.

It is an arithmetic number, because the mean of its divisors is an integer number (56515066497).

Almost surely, 2113030132993 is an apocalyptic number.

It is an amenable number.

113030132993 is a deficient number, since it is larger than the sum of its proper divisors (1).

113030132993 is an equidigital number, since it uses as much as digits as its factorization.

113030132993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 35.

The spelling of 113030132993 in words is "one hundred thirteen billion, thirty million, one hundred thirty-two thousand, nine hundred ninety-three".