Base | Representation |
---|---|
bin | 10000011100101011101… |
… | …110110110100000101001 |
3 | 11000001112020212102202022 |
4 | 100130223232312200221 |
5 | 122004333341213113 |
6 | 2223131324114225 |
7 | 144443065223021 |
oct | 20345356664051 |
9 | 4001466772668 |
10 | 1130310101033 |
11 | 3a63a8648573 |
12 | 16308a695975 |
13 | 827844969b9 |
14 | 3c9c8b94a81 |
15 | 1e606931908 |
hex | 1072bbb6829 |
1130310101033 has 2 divisors, whose sum is σ = 1130310101034. Its totient is φ = 1130310101032.
The previous prime is 1130310101029. The next prime is 1130310101047. The reversal of 1130310101033 is 3301010130311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 784434376489 + 345875724544 = 885683^2 + 588112^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130310101033 - 22 = 1130310101029 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130310101083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565155050516 + 565155050517.
It is an arithmetic number, because the mean of its divisors is an integer number (565155050517).
Almost surely, 21130310101033 is an apocalyptic number.
It is an amenable number.
1130310101033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130310101033 is an equidigital number, since it uses as much as digits as its factorization.
1130310101033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1130310101033 its reverse (3301010130311), we get a palindrome (4431320231344).
The spelling of 1130310101033 in words is "one trillion, one hundred thirty billion, three hundred ten million, one hundred one thousand, thirty-three".
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