Base | Representation |
---|---|
bin | 10000011100101011111… |
… | …110100100111011000101 |
3 | 11000001112112121212102220 |
4 | 100130223332210323011 |
5 | 122004340420121201 |
6 | 2223131552322553 |
7 | 144443145242214 |
oct | 20345376447305 |
9 | 4001475555386 |
10 | 1130314223301 |
11 | 3a63aaa036aa |
12 | 16308bb43459 |
13 | 827852ab103 |
14 | 3c9c954907b |
15 | 1e606e98036 |
hex | 1072bfa4ec5 |
1130314223301 has 8 divisors (see below), whose sum is σ = 1586405927520. Its totient is φ = 713882667312.
The previous prime is 1130314223287. The next prime is 1130314223323. The reversal of 1130314223301 is 1033224130311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1130314223301 - 218 = 1130313961157 is a prime.
It is a super-2 number, since 2×11303142233012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130314225301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9915036990 + ... + 9915037103.
It is an arithmetic number, because the mean of its divisors is an integer number (198300740940).
Almost surely, 21130314223301 is an apocalyptic number.
It is an amenable number.
1130314223301 is a deficient number, since it is larger than the sum of its proper divisors (456091704219).
1130314223301 is a wasteful number, since it uses less digits than its factorization.
1130314223301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19830074115.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1130314223301 its reverse (1033224130311), we get a palindrome (2163538353612).
The spelling of 1130314223301 in words is "one trillion, one hundred thirty billion, three hundred fourteen million, two hundred twenty-three thousand, three hundred one".
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