113031441134114 has 4 divisors (see below), whose sum is σ = 169547161701174. Its totient is φ = 56515720567056.

The previous prime is 113031441134041. The next prime is 113031441134137. The reversal of 113031441134114 is 411431144130311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 93851201908489 + 19180239225625 = 9687683^2 + 4379525^2 .

It is a super-3 number, since 3×113031441134114³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28257860283527 + ... + 28257860283530.

Almost surely, 2^{113031441134114} is an apocalyptic number.

113031441134114 is a deficient number, since it is larger than the sum of its proper divisors (56515720567060).

113031441134114 is an equidigital number, since it uses as much as digits as its factorization.

113031441134114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56515720567059.

The product of its (nonzero) digits is 6912, while the sum is 32.

Adding to 113031441134114 its reverse (411431144130311), we get a palindrome (524462585264425).

The spelling of 113031441134114 in words is "one hundred thirteen trillion, thirty-one billion, four hundred forty-one million, one hundred thirty-four thousand, one hundred fourteen".