Base | Representation |
---|---|
bin | 1010010001111100011101… |
… | …0110000110001101010001 |
3 | 1111000121001121201001211222 |
4 | 2210133013112012031101 |
5 | 2440143332233224403 |
6 | 40012413431414425 |
7 | 2244433605513551 |
oct | 244370726061521 |
9 | 44017047631758 |
10 | 11303403414353 |
11 | 3668823603846 |
12 | 1326812b24415 |
13 | 63cba23a28bb |
14 | 2b11326d3161 |
15 | 149062a47338 |
hex | a47c7586351 |
11303403414353 has 2 divisors, whose sum is σ = 11303403414354. Its totient is φ = 11303403414352.
The previous prime is 11303403414313. The next prime is 11303403414377. The reversal of 11303403414353 is 35341430430311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7248306983824 + 4055096430529 = 2692268^2 + 2013727^2 .
It is a cyclic number.
It is not a de Polignac number, because 11303403414353 - 232 = 11299108447057 is a prime.
It is not a weakly prime, because it can be changed into another prime (11303403414313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651701707176 + 5651701707177.
It is an arithmetic number, because the mean of its divisors is an integer number (5651701707177).
Almost surely, 211303403414353 is an apocalyptic number.
It is an amenable number.
11303403414353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303403414353 is an equidigital number, since it uses as much as digits as its factorization.
11303403414353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 11303403414353 its reverse (35341430430311), we get a palindrome (46644833844664).
The spelling of 11303403414353 in words is "eleven trillion, three hundred three billion, four hundred three million, four hundred fourteen thousand, three hundred fifty-three".
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